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23 vote

What least number must be subtracted from 1936 so that the resulting number when divided by 9, 10 and 15 will leave in each case the same remainder 7

Asked on by | Votes 23 | Views: 843 | Tags: mathematics     | hcf and lcm     | quantitative aptitude     | ssc     | Add Bounty

What least number must be subtracted from 1936 so that the resulting number when divided by 9, 10 and 15 will leave in each case the same remainder 7
1). 37
2). 36
3). 39
4). 30

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2 answers

24 vote
Answered by on | Votes 24 | | Last Updated: 2021-08-12 13:29:01

39

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23 vote
Answered by on | Votes 23 |
LCM of 9, 10 and 15 = 90 Þ The multiple of 90 are also divisible by 9, 10 or 15. \ 21 × 90 = 1890 will be divisible by them. \ Now, 1897 will be the number that will give remainder 7. 1936 – 1897 Required number = 1936 – 1897 = 39
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