What least number must be subtracted from 1936 so that the resulting number when divided by 9, 10 and 15 will leave in each case the same remainder 7
What least number must be subtracted from 1936 so that the resulting number when divided by 9, 10 and 15 will leave in each case the same remainder 7 1). 37 2). 36 3). 39 4). 30
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Answered by
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2018-01-20 03:45:31 | Votes
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# | Last Updated:
2021-08-12 13:29:01
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Answered by
Guest on
2018-04-09 19:24:35 | Votes
23 |
#
LCM of 9, 10 and 15 = 90
Þ The multiple of 90 are also divisible
by 9, 10 or 15.
\ 21 × 90 = 1890 will be divisible
by them.
\ Now, 1897 will be the number
that will give remainder 7.
1936 – 1897
Required number
= 1936 – 1897 = 39
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