The sum of two numbers is 84 and their HCF is 12. Total number of such pairs of number is
The sum of two numbers is 84 and their HCF is 12. Total number of such pairs of number is
1). 2
2). 3
3). 4
4). 5
2 answers
HCF $\large= 12$ Numbers $\large= 12x$ and $\large 12y$ where $\large x$ and $\large y$ are prime to each other.
$\large 12x + 12y = 84 12 (x + y) = 84 x + y =\frac{84}{12} = 7$
Possible pairs of numbers satisfying this condition $\large= (1,6), (2,5) and (3,4)$
Hence three pairs are of required numbers
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