The LCM of two numbers is 44 times of their HCF. The sum of the LCM and HCF is 1125. If one number is 25, then the other number is
The LCM of two numbers is 44 times of their HCF. The sum of the LCM and HCF is 1125. If one number is 25, then the other number is 1). 1100 2). 975 3). 900 4). 800
SSC CGL Books
2 answers
Answered by
Guest on
2018-01-20 03:47:33 | Votes
1 |
#
is option 1 is the correct answer am i right
Join Telegram Group
Answered by
Guest on
2018-04-10 22:42:11 | Votes
2 |
#
If the HCF = H, then
LCM = 44 H
44 H + H = 1125
45 H = 1125
H =$\frac{1125}{45}$ =25
LCM = 44 × 25 = 1100
Now
First number × Second number
= LCM × HCF
25 × Second number
= 1100 × 25
Second number
$\frac{1100\times25}{25}$ = 1100
Other Questions
1. Two numbers are in the ratio 3:4.The product of their H.C.F. and L.C.M. is 2028. The sum of the numbers is
2. Three numbers are in the ratio 2:3:4 and their H.C.F. is 12. The L.C.M. of the numbers is
3. LCM of two numbers is 2079 and their HCF is 27. If one of the number is 189, the other number is
4. The least number, which when divided by 12. 15. 20 or 54 leaves a remainder of 4 in each case, is :
5. If A nad B are the H.C.F and L.C.M. respectively of two algebraic expressions x and y, and A + B = x + y, then the value of $A^{3}+B^{3}$ is
6. Let the least number of six digits which when divided by 4, 6, 10, 15 leaves in each case same remainder 2 be N. The sum of digits in N is :
7. The HCF of two numbers is 15 and their LCM is 300. If one of the number is 60, the other is :
8. HCF and LCM of two numbers are 7 and 140 respectively. If the numbers are between 20 and 45, the sum of the numbers is :
9. H.C.F of $\frac{2}{3}$ , $\frac{4}{5}$, and $\frac{6}{7}$ is :
10. The least number which when divided by 4. 6. 8. 12 and 16 leaves a remainder of 2 in each case is :