A pipe of diameter d can drain a certain water tank in 40 minutes. The time taken by a pipe of diameter 2d for doing the same job in : 1). 5 minutes 2). 10 minutes 3). 20 minutes 4). 80 minutes
Time is inversely proportional to the square of diameter. So,
$ \frac{t1}{t2} = \frac{(d2)^2}{(d1)^2} $
$\frac{40}{t2} = \frac{(2d)^2}{(d)^2}$
Solve, t2 = $10$ mins