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The value of $\frac{(3.2)^{3} - 0.008}{(3.2)^{2} + 0.64 + 0.04}$ is

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The value of $\frac{(3.2)^{3} - 0.008}{(3.2)^{2} + 0.64 + 0.04}$ is
1). 0
2). 2.994
3). 3.208
4). 3

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Answered by on | Votes 0 |
Correct answer is: 3

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