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Among three numbers, the first is twice the second and thrice the third. If the average of three numbers is 396, then what is the difference between the first and the third number?

Among three numbers, the first is twice the second and thrice the third. If the average of three numbers is 396, then what is the difference between the first and the third number?
1). 594
2). 448
3). 432
4). 453

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Guest · Answer 1 · 2018-06-11 11:24:32

22 vote

Answered by Guest on 2018-06-11 11:24:32 | Votes 22 | #

I think 432 is right

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Alin Malya Rashmi G · Answer 2 · 2021-09-18 11:43:53

Solution:

Let the three number be 'x' , 'y' and 'z'.

Given: x = 2y and x = 3z

So, y = x/2 and z = x/3

The average of three numbers = 396

That is, (x + y + z )/3 = 396

x + y + z = 396 × 3

So, x + y + z = 1188

Substituting the values we get,

x + (x/2) + (x/3) = 1188

(6x + 3x + 2x)/6 = 1188

11x/6 = 1188

x = 1188 × (6/11)

x = 108 × 6

x = 648

So, y = 648/2

y = 324

and z = 648/3

z = 216

Now the difference between the first and third number = 648 - 216

x - z = 432

So,the correct option is 3). 432

Among three numbers, the first is twice the second and thrice the third. If the average of three numbers is 396, then what is the difference between the first and the third number?

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