If $\frac{a^{2}}{b+c}=\frac{b^{2}}{c+a}=\frac{c^{2}}{a+b}=1$ then find the value of $\frac{2}{1+a}+\frac{2}{1+b}+\frac{2}{1+c}$

If $\frac{a^{2}}{b+c}=\frac{b^{2}}{c+a}=\frac{c^{2}}{a+b}=1$ then find the value of $\frac{2}{1+a}+\frac{2}{1+b}+\frac{2}{1+c}$
1). 5
2). 8
3). 2
4). 1

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