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$\frac{1}{secA+tanA}$ is equal to

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$\frac{1}{secA+tanA}$ is equal to
1). cosecA - cotA
2). sinA - cosA
3). secA - tanA
4). sinA + cosA

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2 answers

2 vote
Answered by on | Votes 2 |
secA - tanA

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0 vote
Answered by on | Votes 0 |
Correct answer is: secA - tanA




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