On a certain sum of money lent out at 16% p.a. the difference between the compound Interest for 1 year, payable half yearly, and the simple interest for 1 year is Rs.56. The sum is
1). Rs.1080
2). Rs.7805
3). Rs.8750
4). Rs.5780
Let p= 100%
r=8% because half early and t= 2yr...
c.i= 1st yr=8 and
2nd yr c.i.=8+ 8×8/100= 8+.64
,difference=(8-8+ .64 )=.64 but given 56; .64___56; 1___87.5;. 100___8750 ans.
Rate of interest = 8% per halfyear
Time = 2 half years
Difference of interests = $\frac{PR^{2}}{100}$
56 = $\frac{P\times (8)^{2}}{(100)^{2}}$
P = $\frac{56\times 10000}{64}$
= 8750