A train 240 meters in length crosses a telegraph post in 16 seconds. The speed of the train is?

A train 240 meters in length crosses a telegraph post in 16 seconds. The speed of the train is?
1). 50 Km/hr
2). 52 Km/hr
3). 54 Km/hr
4). 56 Km/hr

SSC CGL Books

---

Join Telegram Group

Answer This Question
Name:
Email:
Answer :
Sum of (3+1)
Submit:

Other Questions

1. If cos(75° - ψ) = sin(60° - θ), then the value of cot(θ + ψ) is (Assume that ψ and θ are both positive acute angles with ψ < 75° and θ < 60°)

2. The value of the following is $\left(\frac{sin47^{0}}{cos43^{0}}\right)^{2} + \left(\frac{cos43^{0}}{sin47^{0}}\right)^{2} - 4cos^{2}45^{0}$

3. If the height of a pole is $2\sqrt{3}$ metre and the length of its shadow is 2 metre, then the angle of elevation of the sun is

4. From the top of a building 60 metre high, the angle of depression of the top and bottom of a tower are observed to be 30° and 60°. The height of the tower in metre is

5. A landmark on the bank of a river are observed from two points A and B on the opposite bank of the river. The lines of sight make equal angles of 30° with the bank of the river. If AB = 3 km, then the width of the river (in kilometre) is

6. What is the value of $Cot 45^{0} + \frac{1}{3} Cosec 60^{0}$?

7. The value of (sinA – 2sin3A)/(2cos3A – cosA) is equal to 

8. What is the value of (2 + tan60o)?

9. If $\theta$ is a positive acute angle and $4cos^{2}\theta - 4 cos\theta + 1$ = 0, then the value of $tan(\theta -15^{0})$ is equal to

10. From a point on a bridge across a river, the angles of depression of the banks are 30° and 45°, respectively. If the brige is at a height of 4 m above the bank, find the width of the river.