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if $\tan(a-\beta)$=1 ,$\sec(a-\beta)$=$\frac{2}{\sqrt{3}}$ and a

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if $\tan(a-\beta)$=1 ,$\sec(a-\beta)$=$\frac{2}{\sqrt{3}}$ and a
1). 5
2). 187$\frac{1}{2}$
3). 8
4). 9

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1 answers

3 vote
Answered by on | Votes 3 |
Right Answer for this question is 187$\frac{1}{2}$

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