if $\tan(a-\beta)$=1 ,$\sec(a-\beta)$=$\frac{2}{\sqrt{3}}$ and a
if $\tan(a-\beta)$=1 ,$\sec(a-\beta)$=$\frac{2}{\sqrt{3}}$ and a
1). 5
2). 187$\frac{1}{2}$
3). 8
4). 9
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Right Answer for this question is 187$\frac{1}{2}$
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