$If, \frac{(a+b)}{\sqrt{ab}}=\frac{2}{1}, \ then\ the\ value\ of \ (a-b)\ is\ equal\ to $

$If, \frac{(a+b)}{\sqrt{ab}}=\frac{2}{1}, \ then\ the\ value\ of \ (a-b)\ is\ equal\ to $
1). 1
2). 0
3). -1
4). 2

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