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Two chords AB and PQ of a circle intersect at D inside a circle. If AD = 4 cm, DB = 6 cm, QD = 3 cm, the length of PQ is equal to

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Two chords AB and PQ of a circle intersect at D inside a circle. If AD = 4 cm, DB = 6 cm, QD = 3 cm, the length of PQ is equal to
1). 11 cm
2). 8 cm
3). 9cm
4). 10 cm

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1 answers

1 vote
Answered by on | Votes 1 |
option 1 is the answer

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