What is the equation of the line if its slope is $\frac{3}{4}$ and y-intercept is 5?
What is the equation of the line if its slope is $\frac{3}{4}$ and y-intercept is 5?
1). 3x + 4y = -20
2). 3x + 4y = 20
3). 3x - 4y = -20
4). 3x - 4y = 20
2 answers
correct answer was option 3
We know that equation of a line is,
y = mx + c
where m is slope and
c is y - intercept.
Given : m = 3/4 and c = 5
Substituting the given values in the equation we get
y = 3/4 x + 5
y - 5 = 3/4 x
4 (y - 5 ) = 3 x
4y - 20 = 3x
Rearranging the equation we get
3x - 4y = -20
So, the correct option is 4). 3x - 4y = -20
Other Questions
1. The slope of the line passing through the points (7,-2) and (x,1) is -3/10. Find x.
2. What is the reflection of the point (3,-5) in the origin?
3. The solution set of 4x - 3y = 47 and 3x + y = 32 is
4. What is the slope of the line 4x - 8y = 3?
6. Reflection of the point (4,-5) in the y-axis is
8. What is the reflection of the point (-0.5, 6) in the x-axis?
9. P(3,1) and R(-7,5) are vertices of a rhombus PQRS. What is the equation of diagonal QS?