A money-lender borrows money at 4% per annum and pays the Interest at the end of the year. He lends it at 6% per annum compound Interest compounded half yearly and receives the Interest at the end of the year. In this way. he gains Rs.104.50 a year. The amount of money he borrows. Is
1). Rs.6.000
2). Rs.5.500
3). Rs.5.000
4). Rs.4.500
. Let the borrowed amount be x
According to the question
X[($1+\frac{3^{2}}{100}$-1)]
= 104.50
[ Interest is compounded half
yearly]
x [(1.03)2 – 1] – 0.04x
= 104.50
0.0609x – 0.04x = 104.50
0.0209x = 104.5
X = 5000