The sum of money which when given on compound interest at 18% per annum would fetch Rs.960 more when the Interest Is payable half yearly than when It was payable annually for 2 years Is :
1). Rs.60,000
2). Rs.30,000
3). Rs.40,000
4). Rs.50,000
.When the interest is payable half
yearly,
= 9% per half annum
Time = 4 half years
Let the principal be Rs. P
C.I. = P $(1+\frac{(R)^{T}}{100})$ -1
= P [1.4116 – 1] = Rs. 0.4116 P
According to the question
P[$(1+\frac{(18)^{2}}{100})$-1]
= P (1.3924 – 1) = Rs. 0.3924 P
According to the question,
0.4116P – 0.3924P = 960
0.0192P = 960
P = $\frac{960}{0.0192}$
= Rs. 50000