14 men can do a work in 18 days, 15 women can do a work in 24 days. If 14 men work for first three days and 10 women work after that for three days, find the part of work left after that?
14 men can do a work in 18 days, 15 women can do a work in 24 days. If 14 men work for first three days and 10 women work after that for three days, find the part of work left after that?
1). $\frac{3}{4}$
2). $\frac{1}{4}$
3). $\frac{1}{2}$
4). $\frac{1}{6}$
2 answers
Work done by 14 men in 1 day = $\frac{1}{18}$
Work done by 14 men in 3 days = $3 \times \frac{1}{18} = \frac{1}{6}$
Work done by 1 woman in 1 day = $\frac{1}{15 \times 24}$
Work done by 10 women in 3 days = $\frac{10 \times 3}{15 \times 24} = \frac{1}{12}$
Total work done = $\frac{1}{6} + \frac{1}{12} = \frac{1}{4}$
Remaining work = $1 - \frac{1}{4} = \frac{3}{4}$
Work done by 14 men in 1 day = $\frac{1}{18}$
Work done by 14 men in 3 days = $3 \times \frac{1}{18} = \frac{1}{6}$
Work done by 1 woman in 1 day = $\frac{1}{15 \times 24}$
Work done by 10 women in 3 days = $\frac{10 \times 3}{15 \times 24} = \frac{1}{12}$
Total work done = $\frac{1}{6} + \frac{1}{12} = \frac{1}{4}$
Remaining work = $1 - \frac{1}{4} = \frac{3}{4}$