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Trigonometry Practice Questions & Answers

0 vote

 Solve for A for the given equation cos 2A = 1 – cos 2A

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 Solve for A for the given equation cos 2A = 1 – cos 2A

A). 45, 125, 225, 315 degrees

B). 45, 125, 225, 335 degrees

C). 45, 135, 225, 315 degrees

D). 45, 150, 220, 315 degrees

0 vote

 Solve for x in the equation: arc tan (x + 1) + arc tan (x – 1) = arc tan (12)

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 Solve for x in the equation: arc tan (x + 1) + arc tan (x – 1) = arc tan (12)

A). 1.20

B). 1.25

C). 1.34

D). 1.5

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 Solve for x in the given equation: Arc tan (2x) + arc tan (x) = π/4

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 Solve for x in the given equation: Arc tan (2x) + arc tan (x) = π/4

A). 0.149

B). 0.281

C). 0.316

D). 0.421

0 vote

 Evaluate arc cot [2cos (arc sin 0.5)]

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 Evaluate arc cot [2cos (arc sin 0.5)]

A). 30°

B). 45°

C). 60°

D). 90°

24 vote

 Arc tan [2 cos (arc sin [(3^(1/2))/2]) / 2]) is equal to

Asked on by Guest | Votes 24

 Arc tan [2 cos (arc sin [(3^(1/2))/2]) / 2]) is equal to

A). /2

B). /3

C). /4

D). /16