In each of the questions a pair of equations is given. You have to find out the values of x and y and give answer.
I. $2x^2 - 7x + 6 = 0$ II. $4y^2 = 9 $
1 implies $2x^2 - 4x - 3x + 6 = 0$
So, (2x - 3)(x-2) = 0
ie x = 3/2 or x = 2
2 implies y = $ \pm \frac{3}{2}$
So, $ x \geq y $
I. $2x^2 - 7x + 6 = 0$ II. $4y^2 = 9 $
1 implies $2x^2 - 4x - 3x + 6 = 0$
So, (2x - 3)(x-2) = 0
ie x = 3/2 or x = 2
2 implies y = $ \pm \frac{3}{2}$
So, $ x \geq y $
1. What will be the value of n4 - 28n3 + 54n2 - 49n - 130, if n = -1?
3. What is the value of (x) in the following equation ?$$\frac{x^{0\cdot7}}{36}=\frac{9}{x^{1.3}}$$
7. If \(x\; = \frac{1}{{\sqrt 2 \; + 1}}\) then ( x + 1) equals to
8. Find the unit place digit in 71 × 72 × 73 × 74 × 76 × 77 × 78 × 79.
9. Determine the value of x2 + y2 when x3 - y3 = 54, x - y = 18 and xy = 2