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In each of the questions a pair of equations is given. You have to find out the values of x and y and give answer.

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In each of the questions a pair of equations is given. You have to find out the values of x and y and give answer.


I. $$2x^2 - 7x + 6 = 0$$ II. $$4y^2 = 9$$
1). if $$x < y$$
2). if $$x\leq y$$
3). if $$x = y$$
4). if $$x > y$$


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2 answers

0 vote
Answered by on | Votes 0 |
Solution

I. $2x^2 - 7x + 6 = 0$ II. $4y^2 = 9 $

1 implies $2x^2 - 4x - 3x + 6 = 0$

So, (2x - 3)(x-2) = 0

ie x = 3/2 or x = 2

2 implies y = $ \pm \frac{3}{2}$

So, $ x \geq y $

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3 vote
Answered by on | Votes 3 |
Solution

I. $2x^2 - 7x + 6 = 0$ II. $4y^2 = 9 $

1 implies $2x^2 - 4x - 3x + 6 = 0$

So, (2x - 3)(x-2) = 0

ie x = 3/2 or x = 2

2 implies y = $ \pm \frac{3}{2}$

So, $ x \geq y $




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