Number obtained by interchanging the digits of a two digit number is less than the original number by 18, and the sum of the digit is 6 what is the original two-digit number ?
1). 46
2). 24
3). 42
4). 64
Let the original number be 10x + y
10y + x + 18 = 10x + y
x + y = 6
Solving for x and y, we get x = 2 and y = 4
So, the original number = 24
Let the original number be 10x + y
10y + x + 18 = 10x + y
x + y = 6
Solving for x and y, we get x = 2 and y = 4
So, the original number = 24