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In each of these question two equations I & II with variables a & b are given You have to solve both the equations to find the values of a & b Mark answer if a) a<b b) $$a\leq b$$ c) relationship between a & b cannot be established d) a>b e) $$a\geq b$$

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In each of these question two equations I & II with variables a & b are given You have to solve both the equations to find the values of a & b
Mark answer if
a) a

<b
b) $$a\leq b$$
c) relationship between a & b cannot be established
d) a>b
e) $$a\geq b$$
I.$$a^{2}+5a+6=0$$
II.$$b^{2}+7b+12=0$$
1). $$a<b$$
2). $$a \leq b$$
3). Relationship between $$a$$ & $$b$$ cannot be established
4). $$a>b$$


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2 answers

2 vote
Answered by on | Votes 2 |
Solution

$a^{2}+5a+6=0$
i.e (a+2)(a+3)=0
i.e a=-2, a=-3

.$b^{2}+7b+12=0$
i.e (b+4)(b+3)=0
i.e b=-4, b=-3

Hence, we can deduce that $a \geq b$.
Therefore, option E is correct.

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3 vote
Answered by on | Votes 3 |
Solution

$a^{2}+5a+6=0$
i.e (a+2)(a+3)=0
i.e a=-2, a=-3

.$b^{2}+7b+12=0$
i.e (b+4)(b+3)=0
i.e b=-4, b=-3

Hence, we can deduce that $a \geq b$.
Therefore, option E is correct.




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