In each of these question two equations I & II with variables a & b are given You have to solve both the equations to find the values of a & b
Mark answer if
a) a
$a^{2}+5a+6=0$
i.e (a+2)(a+3)=0
i.e a=-2, a=-3
.$b^{2}+7b+12=0$
i.e (b+4)(b+3)=0
i.e b=-4, b=-3
Hence, we can deduce that $a \geq b$.
Therefore, option E is correct.
$a^{2}+5a+6=0$
i.e (a+2)(a+3)=0
i.e a=-2, a=-3
.$b^{2}+7b+12=0$
i.e (b+4)(b+3)=0
i.e b=-4, b=-3
Hence, we can deduce that $a \geq b$.
Therefore, option E is correct.