In each of the questions a pair of equations is given. You have to find out the values of x and y and give answer.

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In each of the questions a pair of equations is given. You have to find out the values of x and y and give answer.

Asked on 2018-06-29 12:17:42 by Guest | Votes 0 | Views: 19 | Tags: sbi | sbi po | sbi po 2002 | algebra | quantitative aptitude | Add Bounty

In each of the questions a pair of equations is given. You have to find out the values of x and y and give answer.

I. $$4x^2 - 4x - 3 = 0$$ II. $$4y^2 + 12y +5 =0$$
1). if $$x < y$$
2). if $$x\leq y$$
3). if $$x = y$$
4). if $$x > y$$

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2 answers

3 vote

Answered by Guest on 2019-04-09 21:42:03 | Votes 3 | #

Solution

I. $4x^2 - 4x - 3 = 0$

implies $4x^2 - 6x + 2x - 3 = 0$

(2x + 1) (2x-3) = 0

So, x = -1/2 or 3/2

II. $4y^2 + 12y +5 =0$

implies $4y^2 + 10y + 2y +5 =0$

(2y + 1) ( 2y + 5) = 0

y = -1/2 or -5/2

So,$ x \geq y$

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2 vote

Answered by Guest on 2019-05-07 21:55:59 | Votes 2 | #

Solution

I. $4x^2 - 4x - 3 = 0$

implies $4x^2 - 6x + 2x - 3 = 0$

(2x + 1) (2x-3) = 0

So, x = -1/2 or 3/2

II. $4y^2 + 12y +5 =0$

implies $4y^2 + 10y + 2y +5 =0$

(2y + 1) ( 2y + 5) = 0

y = -1/2 or -5/2

So,$ x \geq y$

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