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What will come in place of the question mark (?) in the following questions ?

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What will come in place of the question mark (?) in the following questions ?


$$32\frac{3}{4}+28\frac{1}{2}\times5\frac{1}{3}-12\frac{1}{6}=?+5\frac{1}{4}$$
1). $$174\frac{2}{3}$$
2). $$167\frac{1}{3}$$
3). $$166\frac{11}{12}$$
4). $$166\frac{1}{12}$$


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2 answers

1 vote
Answered by on | Votes 1 |
Solution

Expression : $32\frac{3}{4}+28\frac{1}{2}\times5\frac{1}{3}-12\frac{1}{6}=?+5\frac{1}{4}$

=> $\frac{131}{4} + (\frac{57}{2} \times \frac{16}{3}) - \frac{73}{6} = ? + \frac{21}{4}$

=> $? = \frac{131}{4} + 152 - \frac{73}{6} - \frac{21}{4}$

=> $? = 152 + \frac{393 - 146 - 63}{12}$

=> $? = 152 + \frac{46}{3} = 152 + 15\frac{1}{3}$

=> $? = 167\frac{1}{3}$

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3 vote
Answered by on | Votes 3 |
Solution

Expression : $32\frac{3}{4}+28\frac{1}{2}\times5\frac{1}{3}-12\frac{1}{6}=?+5\frac{1}{4}$

=> $\frac{131}{4} + (\frac{57}{2} \times \frac{16}{3}) - \frac{73}{6} = ? + \frac{21}{4}$

=> $? = \frac{131}{4} + 152 - \frac{73}{6} - \frac{21}{4}$

=> $? = 152 + \frac{393 - 146 - 63}{12}$

=> $? = 152 + \frac{46}{3} = 152 + 15\frac{1}{3}$

=> $? = 167\frac{1}{3}$




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