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In each of these question two equations I & II with variables a & b are given You have to solve both the equations to find the values of a & b Mark answer if a) a<b b) $$a\leq b$$ c) relationship between a & b cannot be established d) a>b e) $$a\geq b$$

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In each of these question two equations I & II with variables a & b are given You have to solve both the equations to find the values of a & b
Mark answer if
a) a

<b
b) $$a\leq b$$
c) relationship between a & b cannot be established
d) a>b
e) $$a\geq b$$
I.$$a^{2}+2a+1=0$$
II.$$b^{2}=\pm4$$
1). $$a<b$$
2). $$a \leq b$$
3). Relationship between $$a$$ & $$b$$ cannot be established
4). $$a>b$$


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2 answers

3 vote
Answered by on | Votes 3 |
Solution

We can easily solve equation I to get a = -1
But we cannot solve $b^{2}=\pm4$. Square root of negative number is not a real number.
Hence, we cannot find a value of b. Therefore, we cannot establish a relationship between a and b.

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0 vote
Answered by on | Votes 0 |
Solution

We can easily solve equation I to get a = -1
But we cannot solve $b^{2}=\pm4$. Square root of negative number is not a real number.
Hence, we cannot find a value of b. Therefore, we cannot establish a relationship between a and b.




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