In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer. Give answer :
a:If x < y
b: If x > y
c: If x ? y
d: If x ? y
e: If relationship between x and y cannot be determined ,
I. $15x^{2} + 26x + 8 = 0$
=> $15x^2 + 6x + 20x + 8 = 0$
=> $(3x + 4) (5x + 2) = 0$
=> $x = \frac{-4}{3} , \frac{-2}{5}$
II. $25y^{2} + 15y + 2 = 0$
=> $25y^2 + 5y + 10y + 2 = 0$
=> $(5y + 2) (5y + 1) = 0$
=> $y = \frac{-2}{5} , \frac{-1}{5}$
$\therefore x \leq y$
I. $15x^{2} + 26x + 8 = 0$
=> $15x^2 + 6x + 20x + 8 = 0$
=> $(3x + 4) (5x + 2) = 0$
=> $x = \frac{-4}{3} , \frac{-2}{5}$
II. $25y^{2} + 15y + 2 = 0$
=> $25y^2 + 5y + 10y + 2 = 0$
=> $(5y + 2) (5y + 1) = 0$
=> $y = \frac{-2}{5} , \frac{-1}{5}$
$\therefore x \leq y$