The sum and the difference of two numbers is 120 and 10 respectively. Find the sum of their squares.
The sum and the difference of two numbers is 120 and 10 respectively. Find the sum of their squares.
1). 7000
2). 7250
3). 7375
4). 7500
2 answers
Let the numbers be ‘a’ and ‘b’
Hence, (a + b) = 120 and (a – b) = 10
As we know, (a + b)2 + (a – b)2 = 2(a2 + b2)
⇒ Sum of their squares = (a2 + b2) = [(a + b)2 + (a – b)2]/2
∴ Sum of their squares = [(120)2 + (10)2]/2 = (14400 + 100)/2 = 14500/2 = 7250Let the numbers be ‘a’ and ‘b’
Hence, (a + b) = 120 and (a – b) = 10
As we know, (a + b)2 + (a – b)2 = 2(a2 + b2)
⇒ Sum of their squares = (a2 + b2) = [(a + b)2 + (a – b)2]/2
∴ Sum of their squares = [(120)2 + (10)2]/2 = (14400 + 100)/2 = 14500/2 = 7250Other Questions
1. If 12x = $19^{2} - 11^{2}$, what is the value of x?
4. If (x11 + 1) is divided by (x + 1), the remainder is:
5. AB is the diameter of the circle with centre O and P be a point on its circumference, if
6. Given: 5x -3(2x-7) > 3x - 1 < 7 + 4x; then x can take which of the following values?
7. If $(x-5)^{2}+(y-2)^{2}+(z-9)^{2}$ = 0 , then value of (x + y - z) is
9. If $-\frac{3}{2} + \left(\frac{2}{3}\right)(3x + 9) = $\frac{x}{2}$, then what is the value of x?