A can work 6 times faster than B and takes 40 days less than B to complete the work. In how many days does A and B individual can complete the work?
1). 8 days and 48 days
2). 6 days and 52 days
3). 12 days and 40 days
4). 8 days and 40 days
Let B takes “n” days to complete work individually. So, A takes (n - 40) days.
For same work, Since A is 6 times faster than B takes 6 times more days that A does take.
So we have,
⇒ n = 6(n-40)
⇒ n = 48 days for B.
∴ For A = n-40 = 8 days.