Direction: In the given question, two equations numbered l and II are given. You have to solve both the equations and mark the appropriate answer
I. a2 + 41a + 400 = 0
II. b2 - 20b + 99 = 0I. a2 + 41a + 400 = 0
⇒ a2 + 25a + 16a + 400 = 0
⇒ a(a + 25) + 16(a + 25) = 0
⇒ (a + 25) (a + 16) = 0
Then, a = (-25) or a = (-16)
II. b2 - 20b + 99 = 0
⇒ b2 - 11b - 9b + 99 = 0
⇒ b(b - 11) - 9(b - 11) = 0
⇒ (b - 9) (b - 11) = 0
Then, b = 9 or b = 11
So, when a = (-25), a < b for b = 9 and a < b for b = 11
And when a = (-16), a < b for b = 9 and a < b for b = 11
∴ we can observe that a < b.3. Find the wrong term in the series. 327, 374, 423, 484, 527