Rancho is 50% more efficient than Sundar. Rancho does a work in 4 days. In how many days will Rancho and Sundar finish a work if first day Rancho works alone, second day Sundar works alone and after that they work together?
Rancho is 50% more efficient than Sundar. Rancho does a work in 4 days. In how many days will Rancho and Sundar finish a work if first day Rancho works alone, second day Sundar works alone and after that they work together?
1). 34/10 days
2). 34/9 days
3). 11 days
4). 33/9 days
1 answers
Rancho is 50% more efficient than Sundar.
∴ Number of days taken by Sundar to finish a work = 4 + 50% of 4 = 6
By Unitary method, Work done by Rancho in one day = 1/4
Similarly, work done by Sundar in one day = 1/6
Work done in first two days = $(\frac{1}{4}\; + \;\frac{1}{6}\; = \;\frac{{10}}{{24}})$
Remaining work = $(1 - \frac{{10}}{{24}}\; = \;\frac{7}{{12}})$
Work done in a day if they work together = $(\frac{1}{4}\; + \;\frac{1}{6}\; = \;\frac{{10}}{{24}})$
∴ No. of days taken for doing $(\frac{7}{{12}}\;)$work if they work together =$(\frac{{14}}{{10}})$ days
∴ Total no. of days taken = $(1\; + \;1\; + \;\frac{{14}}{{10}}\; = \;2\frac{7}{5})$