A does half as much work as B is one sixth of the time. If together they take 10 days to complete a work, how much time shall A alone take to do it?
1). 70 days
2). 30 days
3). 14 days
4). 50 days
Given,
⇒ A × 1/6 = B × 1/2
⇒ A = 3B
⇒ $(\frac{A}{B} = \frac{3}{1})$
∴ A’s efficiency = 3 unit / day.
& B’s efficiency = 1 unit / day.
According to Qs.
(A + B) Complete in 10 day
∴ Total Work = (3 + 1) × 10
= 4 × 10 = 40
∴ Time taken by $(A = \frac{{40}}{{13}})$
= 13.33 Days = 14 Days.