Find the value of sin230cos245 + 4tan230 + (1/2)sin290 – 2cos290 + 1/24
1). 3
2). 4
3). 2
4). 1
sin230cos245 + 4tan230 + (1/2)sin290 – 2cos290 + 1/24
(? sin30 = 1/2, cos45 = 1/√2, tan30 = 1/√3, sin90 = 1, cos90 = 0)
= (1/2)2 × (1/√2)2 + 4× (1/√3)2 + (1/2) × 12 – 2× 02 + 1/24
= (1/8) + (4/3) + (1/2) – 0 + (1/24)
= 48/24
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