A is three times as efficient as B and takes 60 days less than B for doing a job. The time in which they can do it together is?

A is three times as efficient as B and takes 60 days less than B for doing a job. The time in which they can do it together is?
1). 15 days
2). 30 days
3). $22\frac{1}{2}days$
4). 60 days

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Guest · Answer 1 · 2019-05-17 07:08:37

Let the number of days in which B does a job be x.

Given, A is three times as efficient as B and takes 60 days less than B for doing a job.

Number of days in which A finishes the job = x – 60

In 1 day, B finishes 1/x of the work.

∴ A finishes 3/x of the work in 1 day.

Thus, A will finish the work in x/3 days.

⇒ x/3 = x – 60

⇒ 2x/3 = 60

⇒ x = 90 days

Thus, B finishes the work in 90 days, while A finishes it in 30 days.

Working together in 1 day, they finish part of work = 1/90 + 1/30

Thus they will finish the work in number of days = 90/4 = $(22\frac{1}{2}days)$

A is three times as efficient as B and takes 60 days less than B for doing a job. The time in which they can do it together is?

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