ExamCompetition Forum Question Papers Ask A Question Mock Test Learn & Earn Sign Up Login Menu



71 vote

In a family of husband, wife and a daughter, the sum of the husband’s age, twice the wife’s age, and thrice the daughter’s age is 85; while the sum of twice the husband’s age, four times the wife’s age, and six times the daughter’s age is 170. It is also given tha

Asked on by | Votes 71 | Views: 719 | Tags: algebra     | quantitative aptitude     | Add Bounty

In a family of husband, wife and a daughter, the sum of the husband’s age, twice the wife’s age, and thrice the daughter’s age is 85; while the sum of twice the husband’s age, four times the wife’s age, and six times the daughter’s age is 170. It is also given that the sum of five times the husband’s age, ten times the wife’s age and fifteen times the daughter’s age equals 450. The number of possible solutions, in terms of the ages of the husband, wife and the daughter, to this problem is
1). 3
2). 2
3). 0
4). Infinite solutions


Share on Facebook      Share on Whatsapp       Share on Twitter




1 answers

41 vote
Answered by on | Votes 41 |

Let the age of husband wife and daughter be denoted by h, w and d respectively

⇒ h + 2w + 3d = 85 - - - - - - - - (i)

⇒ 2h + 4w + 6d = 170 - - - - - - - - (ii)

⇒ 5h + 10w + 15d = 450 - - - - - - - - (iii)

Multiplying the first equation by 5 we get

⇒ 5h + 10w + 15d = 425

But Eq (iii) gives 5h + 10w + 15d = 450

So, No solutions possible

∴ No solutions possible.

Join Telegram Group




Answer This Question

Name:
Email:
Answer :
Sum of (2+4)
Submit: