Rakesh, Ramesh and Suresh went to a market to purchase watches whose costs were same. But each watch was available with two successive discounts. Rakesh availed two successive discounts of 20% and 5%. Ramesh availed two successive discounts of 15% and 10% while Suresh availed two successive discounts of 12% and 13%. Who gets the maximum possible discount?
Rakesh, Ramesh and Suresh went to a market to purchase watches whose costs were same. But each watch was available with two successive discounts. Rakesh availed two successive discounts of 20% and 5%. Ramesh availed two successive discounts of 15% and 10% while Suresh availed two successive discounts of 12% and 13%. Who gets the maximum possible discount?
1). Rakesh
2). Ramesh
3). Suresh
4). All of the above
1 answers
Let the marked price of watches is Rs. 100
For Rakesh,
⇒ First discount = 100 – (20% of 100) = 80
⇒ Second discount = 80 – (5% of 80) = 80 – {(5/100) × 80} = 76
⇒ Total discount = 100 – 76 = 24
For Ramesh,
⇒ First discount = 100 – (15% of 100) = 85
⇒ Second discount = 85 – (10% of 85) = 85 – 8.5 = 76.5
⇒ Total discount = 100 – 76.5 = 23.5
For Suresh,
⇒ First discount = 100 – (12% of 100) = 88
⇒ Second discount = 88 – (13% of 88) = 88 – {(13/100) × 88} = 76.56
⇒ Total discount = 100 – 76.56 = 23.44
∴ Rakesh gets the maximum discount
Alternatively:-
We have a formula of two successive discounts, for two successive discounts a and b,
⇒ Total discount = a + b – (ab/100)
⇒ Rakesh’s discount = 20 + 5 – {(20)(5)/100} = 25 – 1 = 24
⇒ Ramesh’s discount = 15 + 10 – {(15)(10)/100} = 25 – 1.5 = 23.5
⇒ Suresh’s discount = 12 + 13 – {(12)(13)/100} = 25 – 1.56 = 23.44
∴ Rakesh gets the maximum discount