A tank can be filled using pipe A and emptied using pipe B. Pipe B can empty the tank in 12 hrs. When both the pipes are simultaneously opened, the tank is half full in 2 hrs. In how much time can pipe A fill the tank alone?
1). 2 hrs.
2). 3 hrs.
3). 4 hrs.
4). 6 hrs.
Let pipe A can fill the tank in ‘x’ hours
A’s 1 hr. work = 1/x
B’s 1 hr. work = 1/12
When both are opened simultaneously, work done in 2 hours,
⇒ (1/x – 1/12) × 2 = 1/2
⇒ (1/x – 1/12) = 1/4
⇒ 1/x = 1/4 + 1/12
⇒ 1/x = 1/3
⇒ x = 3 hrs.
∴ Pipe A can fill the tank alone in 3 hours