3 numbers whose average is 112, the first number is 1/6th the sum of other 2. What is the first number?
? Average of three numbers is 112
This means sum of 3 numbers is = 112 × 3 = 336
Let the first number be X
Then X = (1/6) × (Sum of other two numbers) = (1/6) × (336 - X)
⇒ X + X/6 = 336/6
⇒ X = 336/7 = 48
∴ First number = 48