In the following question, two statements are numbered as A and B. On solving these statements we get quantities A and B respectively. Solve for the both quantities and chose the correct option.
Quantity A: During a journey of 100 km, a bus covers first 60 km with a speed of 45 kmph and the remaining distance with a speed of 30 kmph. The average speed of the bus during the whole journey in m/s is...
Quantity B: A motorcycle rider 250 km distance of uphill in 5 hr and in return he cover the same distance downhill in 3 hr. The average speed of the rider over the journey in m/s is....Solving for Quantity A -
Total distance need to cover = 100 km
Time taken to cover 60 km = 60/45 = 1.33 hr
Remaining distance need to cover = 100 - 60 = 40 km
Time taken to cover 40 km = 40/30 = 1.33 hr
Total time taken = 1.33 + 1.33 = 2.66 hr
Average speed over 100 km = 100/2.66 = 37.59 kmph
Convert the value of speed in m/s by multiplying 18/5,
Average speed of train = 37.59 × (18/5) = 135.33 m/s
Solving for Quantity B -
For average speed for entire journey,
Total distance cover = 250 + 250 = 500 km
Total time taken = 5 + 3 = 8
Average speed = 500/8 = 62.5 kmph
Convert the value in m/s by multiplying 18/5,
Average speed = 62.5 × (18/5) = 225 m/s
∴ Quantity A < Quantity B