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In the following question, two statements are numbered as A and B. On solving these statements we get quantities A and B respectively. Solve for the both quantities and chose the correct option. Quantity A: During a journey of 100 km, a bus covers first 60 km with a speed of 45 kmph and the remaini

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In the following question, two statements are numbered as A and B. On solving these statements we get quantities A and B respectively. Solve for the both quantities and chose the correct option.

Quantity A: During a journey of 100 km, a bus covers first 60 km with a speed of 45 kmph and the remaining distance with a speed of 30 kmph. The average speed of the bus during the whole journey in m/s is...

Quantity B: A motorcycle rider 250 km distance of uphill in 5 hr and in return he cover the same distance downhill in 3 hr. The average speed of the rider over the journey in m/s is....
1). Quantity A > Quantity B
2). Quantity A < Quantity B
3). Quantity A ≥ Quantity B
4). Quantity A ≤ Quantity B


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Solving for Quantity A -

Total distance need to cover = 100 km

Time taken to cover 60 km = 60/45 = 1.33 hr

Remaining distance need to cover = 100 - 60 = 40 km

Time taken to cover 40 km = 40/30 = 1.33 hr

Total time taken = 1.33 + 1.33 = 2.66 hr

Average speed over 100 km = 100/2.66 = 37.59 kmph

Convert the value of speed in m/s by multiplying 18/5,

Average speed of train = 37.59 × (18/5) = 135.33 m/s

Solving for Quantity B -

For average speed for entire journey,

Total distance cover = 250 + 250 = 500 km

Total time taken = 5 + 3 = 8

Average speed = 500/8 = 62.5 kmph

Convert the value in m/s by multiplying 18/5,

Average speed = 62.5 × (18/5) = 225 m/s

∴ Quantity A < Quantity B

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