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Two objects A and B of masses 1 kg and 3 kg respectively, have equal momentum. What is the ratio of the kinetic energy of A to the kinetic energy of B?
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Two objects A and B of masses 1 kg and 3 kg respectively, have equal momentum. What is the ratio of the kinetic energy of A to the kinetic energy of B?
1). 3 : 1
2). 1 : 1
3). 9 : 1
4). 1 : 3
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m1v1 = m2v2
$(\frac{{{v_1}}}{{{v_2}}} = \frac{{{m_2}}}{{{m_1}}} = \frac{3}{1} = 3)$
$(\frac{{K{E_1}}}{{K{E_2}}} = \frac{\frac{1}{2}{{m_1}v_1^2}}{\frac{1}{2}{{m_2}v_2^2}}= \frac{{{m_1}v_1^2}}{{{m_2}v_2^2}} = \left( {\frac{{{m_1}}}{{{m_2}}}} \right){\left( {\frac{{{v_1}}}{{{v_2}}}} \right)^2} = \frac{1}{3}{\left( 3 \right)^2} = 3)$Other Questions
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