A alone can do a work in 20 days. B is 25% more efficient than A. A and B started working and worked for 4 days. If C alone completed the remaining job in 22 days. How many days C alone takes to complete the entire job?
1). 24 days
2). 36 days
3). 12 days
4). 20 days
A alone can do work in 20 days.
B is 25% more efficient than A.
⇒ B can do a work in 16 days.
Let the total unit of work ( LCM of 20 and 16) = 80 units
⇒ A’s one day work = 4
⇒ B’s one day work = 5
As A and B left after working for 4 days.
⇒ Work done by A and B in 4 days = 36 work
⇒ Work left = 44 units is done by C in 22 days.
⇒ C’s one day work = 2 units
∴ 80 units of work can be completed by C alone in 80/2 = 40 days