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The sum of the ages of a father and son is 38 years. Four years ago, the product of their ages was 3 times the father’s age at that time. The present ages of the father and son, respectively are

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The sum of the ages of a father and son is 38 years. Four years ago, the product of their ages was 3 times the father’s age at that time. The present ages of the father and son, respectively are
1). 28 years, 10 years
2). 32 years, 6 years
3). 31 years, 7 years
4). 34 years, 4 years


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1 answers

4 vote
Answered by on | Votes 4 |

Let’s assume that present age of father is X and age of son is Y

∴ Sum of their present ages = X + Y = 38

Four years ago, the age of father was = X – 4

Four years ago, the age of son was = Y – 4  

? Four years ago, the product of their ages was 3 times the father’s age at that time.

∴ (X – 4) × (Y – 4) = 3 (X – 4)

⇒ Y – 4 = 3

⇒ Y = 7

∴ Present age of son is = 7 years

& present age of father is = 38 – 7 = 31 years

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