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In the given question, two equations numbered l and II are given. You have to solve both the equations and mark the appropriate answer I. a2 + 36a + 324 = 0 II. b2 - 35b + 96 = 0

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In the given question, two equations numbered l and II are given. You have to solve both the equations and mark the appropriate answer

I. a2 + 36a + 324 = 0

II. b2 - 35b + 96 = 0
1). a < b
2). a > b
3). a ≤ b
4). a ≥ b


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Answered by on | Votes 2 |

I. a2 + 36a + 324 = 0

⇒ a2 + 18a + 18a + 324 = 0

⇒ a(a + 18) + 18(a + 18) = 0

⇒ (a + 18) (a + 18) = 0

Then, a = (-18)

II. b2 - 35b + 96 = 0

⇒ b2 - 32b - 3b + 96 = 0

⇒ b(b - 32) - 3(b - 32) = 0

⇒ (b - 3) (b - 32) = 0

Then, b = 3 or b = 32

So, when a = (-18), a < b for b = 3 and a < b for b = 32

∴ we can observe that a < b.

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