In the given question, two equations numbered l and II are given. You have to solve both the equations and mark the appropriate answer
I. a2 + 36a + 324 = 0
II. b2 - 35b + 96 = 0I. a2 + 36a + 324 = 0
⇒ a2 + 18a + 18a + 324 = 0
⇒ a(a + 18) + 18(a + 18) = 0
⇒ (a + 18) (a + 18) = 0
Then, a = (-18)
II. b2 - 35b + 96 = 0
⇒ b2 - 32b - 3b + 96 = 0
⇒ b(b - 32) - 3(b - 32) = 0
⇒ (b - 3) (b - 32) = 0
Then, b = 3 or b = 32
So, when a = (-18), a < b for b = 3 and a < b for b = 32
∴ we can observe that a < b.