A pump can fill a tank with water in 3 hours. Because of a leak it took \(3\frac{1}{5}hours\) to fill the tank. The leak can drain all the water in the tank in
1). 54 hours
2). 36 hours
3). 42 hours
4). 48 hours
The pump can fill the tank in 3 hours
∴ Part of tank filled by the pump in 1 hour = 1/3
Let, the leak can drain all the water in ‘x’ hours
∴ Part of tank leaked by the drain in 1 hour = 1/x
Given, Because of a leak pump took $(3\frac{1}{5}hours = \frac{{16}}{5}hours)$ to fill the tank
$(\therefore \frac{1}{3} \times \frac{{16}}{5} - \frac{1}{x} \times \frac{{16}}{5} = 1)$
⇒ 16/15 - 16/5x = 1
⇒ 16/5x = 16/15 – 1 = 1/15
⇒ 5x = 16 × 15
⇒ x = 48 hours