Three people A, B and C working individually can finish a job in 10, 12 and 20 days respectively. They decided to work together but after 2 days, A left the work and after another one day, B also left work. If they got two lacs collectively for the entire work, find the difference of the highest and lowest share
Let the total work be LCM(10, 12, 20) = 60 units
⇒ Efficiency of A = 60/10 = 6 units/day
⇒ Efficiency of B = 60/12 = 5 units/day
⇒ Efficiency of C = 60/20 = 3 units/day
Since the number of working days are different for each person, the share of each will be calculated in the ratio of the units of work done
Now, A works for 2 days and B works for 3 days
⇒ Work done by A = 2 x 6 = 12 units
⇒ Work done by B = 3 x 5 = 15 units
⇒ Work done by C = 60 – 12 – 15 = 33 units
Therefore, ratio of work done = 12 : 15 : 33 = 4 : 5 : 11
⇒ A’s share = (4/20) x 2,00,000 = Rs 40,000
⇒ B’s share = (5/20) x 2,00,000 = Rs 50,000
⇒ C’s share = (11/20) x 2,00,000 = Rs 1,10,000
Difference of the highest and lowest share = Rs 1,10,000 – 40,000 = Rs 70,000
∴ Difference is of Rs. 70000