Three fair coins are tossed simultaneously. Find the probability of getting one head.
Three fair coins are tossed simultaneously. Find the probability of getting one head.
1).
2/3
2).
1/6
3).
3/8
4).
1/8
1 answers
We know that:
When three fair coins are tossed simultaneously,
The numbers of possible outcomes are n(s) = 23 = 8
The number of favorable outcomes are
n(E) = {HTT, THT, TTH} = 3
Formula: Probability of occurrence of an event $(P\left( E \right) = {{Number\ of\ favorable\ outcomes} \over {Numeber\ of\ possible\ outcomes}} = {{n\left( E \right)} \over {n\left( S \right)}})$
∴Required probability = 3/8
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