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Directions: In the following questions two equations numbered I and II are given. You have to solve both the equations and Give answer: I. \(\frac{{17}}{{\sqrt x }}\) = √x – \(\frac{7}{{\sqrt x }}\) II. y3 – \(\frac{{\left( {3\;\times \;8} \right)\frac{9}{2}}}{{y\sqrt y }}\) = 0

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Directions: In the following questions two equations numbered I and II are given. You have to solve both the equations and Give answer:

I. \(\frac{{17}}{{\sqrt x }}\) = √x – \(\frac{7}{{\sqrt x }}\)

II. y3\(\frac{{\left( {3\;\times \;8} \right)\frac{9}{2}}}{{y\sqrt y }}\) = 0
1). if x > y
2). if x ≥ y
3). if x < y
4). if x ≤ y


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Answered by on | Votes 1 |

I. $(\frac{{17}}{{\sqrt x }} = \sqrt x - \frac{7}{{\sqrt x }} = 0)$

⇒ $(\frac{{17}}{{\sqrt x }})$ + $(\frac{7}{{\sqrt x }} = \sqrt x)$

⇒ $(\frac{{17\; + \;7}}{{\sqrt x }})$ = √x

⇒ 24 = x

II. y3 – $(\frac{{\left( {3\; \times \;8} \right)\frac{9}{2}}}{{y\sqrt y }})$ = 0

⇒ y9/2 = 249/2

⇒ y = 24

When x = 24, x = y for y = 24

∴ x = y

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