Directions: In the following questions two equations numbered I and II are given. You have to solve both the equations and Give answer:
I. \(\frac{{17}}{{\sqrt x }}\) = √x – \(\frac{7}{{\sqrt x }}\)
II. y3 – \(\frac{{\left( {3\;\times \;8} \right)\frac{9}{2}}}{{y\sqrt y }}\) = 0I. $(\frac{{17}}{{\sqrt x }} = \sqrt x - \frac{7}{{\sqrt x }} = 0)$
⇒ $(\frac{{17}}{{\sqrt x }})$ + $(\frac{7}{{\sqrt x }} = \sqrt x)$
⇒ $(\frac{{17\; + \;7}}{{\sqrt x }})$ = √x
⇒ 24 = x
II. y3 – $(\frac{{\left( {3\; \times \;8} \right)\frac{9}{2}}}{{y\sqrt y }})$ = 0
⇒ y9/2 = 249/2
⇒ y = 24
When x = 24, x = y for y = 24
∴ x = y