The arithmetic mean of 9 numbers is 100 and the average of three of them is 40. What is the average of other six numbers?
$(Average = \frac{{sum}}{{Number\;of\;terms}})$
⇒ Sum = Average × Number of terms
Let the sum of other six numbers be x, then as per question
Sum of 9 numbers = Sum of 3 numbers + sum of other 6 numbers
⇒ 100 × 9 = 40 × 3 + x
⇒ x = 900 – 120 = 780
∴ Average of other six numbers = 780/6 = 130