A train running at 7/11 of its own regular speed reached a place in 22 hours. How much time could be saved if the train ran at its regular speed?
1). 14 hours
2). 7 hours
3). 8 hours
4). 16 hours
Let the original speed of train be X km/hr
∴ changed speed of train = 7X/11 km/hr
We know that, distance traveled = speed × time taken
⇒ Total distance traveled by train$(= \;\frac{{7X}}{{11}}\; \times \;22\; = \;14X)$
If train travels with its original speed-
∴ Time taken to travel = (total distance)/(speed of train)
⇒ Time taken to travel with regular speed = 14X/X = 14 hrs
∴ time saved = 22 – 14 = 8 hours