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Directions: In the following questions, two equations numbered I and II are given. You have to solve both the equations and give an answer. I. 12/√x – 23/√x = 5√x II. √y/12 – 5√y/12 = 1/√y

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Directions: In the following questions, two equations numbered I and II are given. You have to solve both the equations and give an answer.

I. 12/√x – 23/√x = 5√x

II. √y/12 – 5√y/12 = 1/√y


1). x > y
2). x ≥ y
3). x < y
4). x ≤ y


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1 answers

3 vote
Answered by on | Votes 3 |

Solving equation I

⇒ 12 – 23 = 5√x × √x

⇒ – 11 = 5x

⇒ x = – 11/5

Solving equation II

⇒ (√y – 5√y)/12 = 1/√y

⇒ – 4√y × √y = 12

⇒ – 4y = 12

⇒ y = – 3

when x = – 11/5, y = – 3

This condition satisfies x > y

∴ x > y

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