Find the quadratic equation whose roots are 3 more than the roots of the equation x2 – 2x – 24 = 0.
Find the quadratic equation whose roots are 3 more than the roots of the equation x2 – 2x – 24 = 0.
1). x2 – 8x- 9 = 0
2). x2 – 8x – 16 = 0
3). x2 + 12x – 36 = 0
4). x2 – 6x + 16 = 0
1 answers
The roots of the given quadratic equation x2 – 2x – 24 = 0 are 6 and -4.
∴ According to the given condition, the roots of the new equation are (6 + 3) and (-4 + 3) i.e. 9, -1
A quadratic equation in ‘x’ can be represented as
x2 – (sum of the roots) + Product of the roots = 0
∴ The required equation will be,
x2 – (9 – 1)x + 9 × -1 = 0
x2 – 8x - 9 = 0
Other Questions
5. Given: 2x - 4 ≤ 2 - x/3 and 2(2x + 5) > 3x - 5, then x can take which of the following values?
6. What is the value equation a3 + b3 + c3 - 3abc if a2 + b2 + c2 = ab + bc + ca + 4 and a + b + c = 4.
7. In a $\triangle ABC$, if $2\angle A$ = $3\angle B$ = $6\angle C$, value of $\angle B$ is
8. if 2x+$\frac{1}{4x}$=1, then value of $x^{2}+\frac{1}{64x^{2}}$ is
9. A number is increased by 84, it becomes 107% of itself. What is the number?