Quadratic equation corresponding to the roots (3 + √7) and (3 – √7) is
1). x2 – 6x + 2 = 0
2). x2 + 6x – 2 = 0
3). x2 – 6x – 2 = 0
4). x2 + 6x + 2 = 0
The quadratic equation corresponding to the roots α and β is x2 – (α + β) x + αβ = 0
In the given questions,
α = 3 + √7
β = 3 - √7
By substituting the values of α and β in the above equation, we get
x2 – (3 + √7 + 3 - √7) x + (3 + √7)(3 - √7) = 0
⇒ x2 – 6x + (9 – 7) = 0
⇒ x2 – 6x + 2 = 03. ‘O’ is the circumcentre of triangle ABC. If $\angle BAC$ = $50^{0}$ then $\angle OBC$ is
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