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Quadratic equation corresponding to the roots (3 + √7) and (3 – √7) is

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Quadratic equation corresponding to the roots (3 + √7) and (3 – √7) is
1). x2 – 6x + 2 = 0
2). x2 + 6x – 2 = 0
3). x2 – 6x – 2 = 0
4). x2 + 6x + 2 = 0


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Answered by on | Votes 0 |

The quadratic equation corresponding to the roots α and β is x2 – (α + β) x + αβ = 0

In the given questions,

α = 3 + √7

β = 3 - √7

By substituting the values of α and β in the above equation, we get

x2 – (3 + √7 + 3 - √7) x + (3 + √7)(3 - √7) = 0

⇒ x2 – 6x + (9 – 7) = 0

⇒ x2 – 6x + 2 = 0

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